Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 28 students, she finds 4 who eat cauliflower. Obtain an a 99% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. . . . Construct and interpret the 99% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) O A. One is 99% confident that the proportion of students who eat cauliflower on Jane's campus is between and O B. There is a 99% chance that the proportion of students who eat cauliflower on Jane's campus is between and O C. The proportion of students who eat cauliflower on Jane's campus is between and 99% of the time. O D. There is a 99% chance that the proportion of students who eat cauliflower in Jane's sample is between and