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java Estructure.com/courses/50050/assignments/674395?module_item_id=1340461 source files. (Math: approximate the square root) There are several techniques for implementing the sqrt(square root) method in the Math class. One such

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Estructure.com/courses/50050/assignments/674395?module_item_id=1340461 source files. (Math: approximate the square root) There are several techniques for implementing the sqrt(square root) method in the Math class. One such technique is known as the Babylonian method. It approximates the square root of a number, n, by repeatedly performing a calculation using the following formula: nextGuess = (lastGuess+n/lastGuess)/2 When nextGuess and lastGuess are almost identical, nextGuess is the approximated square root. The initial guess can be any positive value (e.g., 1). This value will be the starting value for lastGuess. If the difference between nextGuess and lastGuess is less than a very small number, such as0.0001, you can claim that nextGuess is the approximated square root of n. If not, nextGuess becomes lastGuess and the approximation process continues. Implementthe following method that returns the square root of n. public static double sqrt(double n) Download the sample program from "Demo Files", LabExercise3.java Sample output: LabExercise 2 (Java Application) /Library/Java/Java Enter a positive number: 199 such as0.0001, you can claim that nextGuess is the approximated square root of n. If not, nextGuess becomes lastGuess and the approximation process continues. Im following method that returns the square root of n. public static double sqrt(double n) Download the sample program from "Demo Files", LabExercise3.java a Sample output: LabExercise 2 [Java Application] /Library/Java/Java Enter a positive number: 199 The square root for 199.0 is 14.106735979665888 LabExercise 2 (Java Application] Enter a positive number: 169 The square root for 169.0 is 13.0 Lab Exercise (1)

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