Java program

Write a method called kthLargest() that accepts an integer x and an array a of integers as its parameters. It should then return the elements that that k elements of greater or equal value. So if k = 0 return the largest element. If k = 1. return the second-largest element, and so on. Do not change the array itself, but you can make a copy if you want.

For example if array1 = {74, 85, 102, 99, 101, 56, 84} and the function kthLargest(2, array1) is called, then your method should return 99 because there are two values that are larger than 99. (101 and 102).

If x is less than zero or greater than/equal to the the size of the array then return -9999;

Make sure your main function works for the following

public static void main(String[] args) { int[] array1 = {6, 8, 2, 3, 5, 12, 16, 1, 7, 4, 21, 19}; int answer = kthLargest(0,array1); System.out.println(answer); answer = kthLargest(1,array1); System.out.println(answer); answer = kthLargest(2,array1); System.out.println(answer); answer = kthLargest(10,array1); System.out.println(answer); answer = kthLargest(11,array1); System.out.println(answer); answer = kthLargest(-1,array1); System.out.println(answer); answer = kthLargest(20,array1); System.out.println(answer); }