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Jennifer, a golfer, has a sample driving distance mean of244.0 yards from16 drives. Jennifer still claims that her average driving distance is225 yards, and the
Jennifer, a golfer, has a sample driving distance mean of244.0
yards from16
drives. Jennifer still claims that her average driving distance is225
yards, and the high average can be attributed to chance. At the2%
significance level, does the data provide sufficient evidence to conclude that Jennifer's mean driving distance is greater than225
yards? Given the sample data below, accept or reject the hypothesis.
- H
- 0
- :=225yards
- ;H
- a
- :>225yards
- =0.02
- (significance level)
- z
- 0
- =2.51
- p=0.006
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