Jill throws a snowball over her house in an attempt to hit her brother, Peter, on the other side. The following equation represents the height of the snowball and the elapsed time until the snowball hits the ground next to Peter. Let: h= height of snowball (ft), t = time (sec) ft Equation: h=-16- sec2 t2+40t+5ft sec or without all the measurement units, h =-16t + 40t+5 Note: Sometimes for gravity we use -32 ft/sec or -16 ft/sec. If we are using metric units we use units that reflect meters typically instead of feet or -9.8 m/sec. 1) At 1.25 seconds, the snowball reaches the peak of its trajectory. How high did Jill throw the snowball? 2) How high was the snowball just before it left Jill's hand? 3) About how long did the snowball fly through the air before striking the ground? (When would h=0 ft?) 4) Using the information from questions #1-3, sketch the graph the represents the snowballs height vs. time. 50 40 30 -20 10 5) From the equation, can we estimate Jill's height? 6) From the equation, how fast was the snowball traveling when it left Jill's hand? 7) Rewrite an equation if Jill climbed up on the shed roof and threw the snowball at a speed of 30 ft/sec. The shed roof is 15ft off the ground. Assume Jill threw it in a similar manner to the first time. 8) How long will it take for the snowball to hit the ground next to Peter on the other side of the house? After show several attempts to figure out the time, check your final solution using Desmos.