Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Just need help coding a fragment for this question in C++ below, I have highlighted the part that needs coding/fixing: Question: You can compute the

Just need help coding a fragment for this question in C++ below, I have highlighted the part that needs coding/fixing:

Question:

You can compute the current index from i by subtracting i from begin(distances), i.e., index = i - begin(distances);.

The last step is to output the name of the closest matching colour if it was found, i.e.,

cout << colour_names[index] << ' '; 

But it is possible that index is invalid, so remember to write an if statement to check whether or not index is invalid first. If index is invalid, then do the following:

cout << "ERROR occurred. Aborting... ";

return 1;

Finally close the loop's brace and write the closing brace of main().

//////////////////////////////////////////////////////////////////////////Code Below/////////////////////////////////////////////////////////////////

#include // for std::sqrt #include // for std::array #include // for std::vector #include // for std::numeric_limits #include // for std::string #include // for std::istream #include // for std::ostream #include // for std::cin, std::cout #include // for std::transform

using namespace std; // place this after the #includes

struct rgb { unsigned char red; unsigned char green; unsigned char blue; };

istream& operator >>(istream& is, rgb& colour) { unsigned r, g, b; is >> r >> g >> b; if(r <= 255 && g <= 255 && b <= 255) { colour.red = r; colour.green = g; colour.blue = b; } return is; }

ostream& operator <<(ostream& os, rgb const& colour) { os << static_cast(colour.red) << " " << static_cast(colour.green) << " " << static_cast(colour.blue); return os; } double distance(rgb const& a, rgb const& b) { double A = 0.0; double x =(a.red - b.red); double y =(a.green - b.green); double z =(a.blue - b.blue); A = x*x + y*y +z*z; A = sqrt(A); return A; } int main() { array const colours{{ { 0x00, 0x00, 0x00 }, // 0: black { 0x80, 0x00, 0x00 }, // 1: maroon { 0x00, 0x80, 0x00 }, // 2: green { 0x80, 0x80, 0x00 }, // 3: olive { 0x00, 0x00, 0x80 }, // 4: navy { 0x80, 0x00, 0x80 }, // 5: purple { 0x00, 0x80, 0x80 }, // 6: teal { 0xC0, 0xC0, 0xC0 }, // 7: silver { 0x80, 0x80, 0x80 }, // 8: grey { 0xFF, 0x00, 0x00 }, // 9: red { 0x00, 0xFF, 0x00 }, // 10: lime { 0xFF, 0xFF, 0x00 }, // 11: yellow { 0x00, 0x00, 0xFF }, // 12: blue { 0xFF, 0x00, 0xFF }, // 13: fushsia { 0x00, 0xFF, 0xFF }, // 14: aqua { 0xFF, 0xFF, 0xFF } // 15: white }};

array const colour_names{ "black", "maroon", "green", "olive", "navy", "purple", "teal", "silver", "gray", "red", "lime", "yellow", "blue", "fushsia", "aqua", "white" };

for(rgb value{}; cin >> value;) { vector distances; distances.reserve(colours.size()); transform(

begin(colours), end(colours), back_inserter(distances), [&value](auto const& colour) { return distance(colour, value); } ); size_t index = std::numeric_limits::max(); double smallest_distance = std::numeric_limits::max(); for(auto i=begin(distances), iEnd=end(distances); i != iEnd; ++i) { cout << *i << (index = i - begin(distances)); //NEED TO FIX cout << colour_names[index] << ' '; //CODE HERE } } }

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Hands On Database

Authors: Steve Conger

1st Edition

013610827X, 978-0136108276

More Books

Students also viewed these Databases questions

Question

Explain the various techniques of Management Development.

Answered: 1 week ago