K L return 4 Evaluate ( 18 , 0 7 7 ( 13 , 0 ) 2e- axis M IK. 4 = ( oct 2 ) 3+5 & the coordinate ances: 9- axio (0 ) com 2 de = WN 2 0 . 4= - x2+4 ( - y 13 / 2 + 3 xetl 2 - 10 e - x 2 + 4 = w/ r 15 - 20 2 - 4/4 50 X = 2 of * = -2 X 4 W/ N 3- 2x TA 2b. (0/ 4 ) U TA = 7 XA = 28 C. - 54x50 -xt4 dx =[ -x + 4 x - 5 3 TA - 85 5x4720 TA 3 XC () 20.41 =((-52 +4(-5)) = 6.33 13 3. ye - (ctl) (2 -5), x=a 04a$5 A = 24 4. f= 2 " xe = - 3 x = a a> - 3 A = 9 0k y= (x+2)3 +5 and the coordinate axes 2 Consider the curve y = -x2 + 4. a Find the x-intercepts of this curve. b Find the point where this curve cuts the y-axis. The following graph shows a piecewise function fmade up of a horizontal line segment and part of the parabola y = -x2 + 4. The area under the graph of fand above the x-axis has been shaded. y=-x+4 X X =-5c Find the area under the graph of f in the 4 The region bounded by the graph of interval 5 S x S 0. fix] = 2\" and the x-axis between x = 3 and d i Write down an expression for the x = a where a > 3 has area equal to 9. Find area under the graph of f and above the value 01 11- Give YOlll' answer correct to the x-axis for x > 0. 4 signicant gures. it Find the area. I Find the shaded area. 3 The region bounded by the graph of x] = {x + \"{x 5]. the x-axis. the y-axis and the line x: a where D S a S S has area equal to 24. Find the value 0! a. \f