$$klar$$ tek tek $$z$$ml$$ bir $$ekilde yapabilir misin $?$

You want to apply a coating via a metallothermic reduction. The substrate material is a steel alloy containing

$0\mathrm{.}16$ wt$.\%$ C$,1\mathrm{.}3$ wt$.\%$ Si$,1\mathrm{.}0$ wt$.\%Mn,8\mathrm{.}9$ wt$.\%$ Cr$,5\mathrm{.}1$ wt$.\%Ni,$ and the rest Fe$.$ The substrate is

cylindrical with a $11\mathrm{.}9cm$ diameter and $5\mathrm{.}3cm$ height.

The coating material is a nickel$-$based superalloy with a targeted composition of $21\mathrm{.}0wt\%Cr,10\mathrm{.}0wt.\%$

$Fe,5\mathrm{.}9wt\%Nb,5\mathrm{.}3wt\%Ti,3\mathrm{.}6wt\%Mo,1\mathrm{.}1wt\%Co,$ and rest Ni$.$ To produce this superalloy, you will

use a metal$-$oxide mixture $)$ and metallic $Al$ powder.

Your goal is to produce a $5\mathrm{.}6mm$ average coating layer onto the top surface of the steel substrate.

a$)$ Calculate the amount of the raw materials to obtain the mentioned coating layer $($g of compounds$).$

b$)$ Calculate the adiabatic temperature of the metallothermic reaction while assuming all the mixtures are at

room temperature or $K).$

If the reduction efficiencies of the metals follow: $91\%Ni,89\%Cr,90\%Fe,53\%Nb,36\%Ti,71\%$

$Mo,89\%Co$; the unreacted $Al$ passes into the superalloy; unreacted metal oxides pass into the slag:

c$)$ Calculate the final composition of the coating layer $($wt$.\%$ of elements$).$

d$)$ Calculate the average height of the coating layer $(mm).$

e$)$ Calculate the amount of the slag $($g$).$

f$)$ Calculate the composition of the slag $($wt$.\%$ of oxides$).$

g$)$ Calculate the final temperature of the substrate $($initially $25C)$ that coated with Ni$-$superalloy or $K).$

${}_{\text{s}\text{t}\text{e}\text{e}\text{l}}=$

$[7884-190\mathrm{.}4(wt.\%C)-150\mathrm{.}5(wt.\%Si)-4\mathrm{.}7(wt.\%Mn)-7\mathrm{.}2(wt.\%Cr)+7\mathrm{.}3(wt.\%Ni)-0\mathrm{.}30t(C)]k\frac{g}{m^3}$

${}_{Ni-\text{a}\text{l}\text{l}\text{o}\text{y}}=$

$\frac{[(8\mathrm{.}9\%Ni)+(7\mathrm{.}2\%Cr)+(7\mathrm{.}9\%Fe)+(8\mathrm{.}4\%Nb)+(4\mathrm{.}5\%Ti)+(10\mathrm{.}2\%Mo)+(8\mathrm{.}9\%Co)+(2\mathrm{.}7\%Al)]}{100}\frac{g}{c}{m}^3$