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The following plan belongs to a two-story building; Design S1-59 slabs in terms of thickness (h, d) and reinforcement (As, s) based on the

The following plan belongs to a two-story building; Design S1-S9 slabs in terms of thickness ( (h, d) ) and reinforcement

( m_{i} ) for one way slab: ( m_{mathrm{A}}=-11 quad m_{1}=10 quad m_{mathrm{Q}}=m_{mathrm{C}}=-9 quad m_{2}=13 qua  

The following plan belongs to a two-story building; Design S1-59 slabs in terms of thickness (h, d) and reinforcement (As, s) based on the following considerations: Material C35/S420 Cover = 25 mm Self-Weight=240 kg.f/m Live Load = 480 kg.f/m hmin-In/24 for one way slab and hmin = ln/36 for two way Slab bw= 40 cm and Columns cross section = 40x40 Ve 1.5 and ys 1.15 Pd= 1.4g+1.6q If you want you can use any available table for mi for Mmax and Vmax or calculate by hand or software, in any case, that you couldn't find you can use the following parameters. Md-pal/m, and Va=2pd*1/3 3.8 m- to 4.6 m 3.3 m 8.2 m S1 $4 S7 -3.2m S2 $5 S8 4.8 m S3 S6 $9 (D mi for one way slab: 3.8 m 4.6 m 3.3 m A MA=-11 3.8 m- 4.6 m 3.3 m MA 8.2 m -16 $1 $4 S7 mi for two way slab: 8.2 m m = 10 mm -9 S1 B $4 33 $7 -3.2m S2 3 B 85 S8 2 m = 13 -3.2m S2 C S5 S8 2 m = 15 mg=me-12 m = 12 4.8 m 83 S6 $9 m3= 10 mp -11 4.8 m S3 S6 DA 89 D my 15 m -16 m = -12 ms=11 m-9 m6=9 m3 = -11 m7 = 11 m = -12 m = -16 my 15 m = -12 me=14 m=-12 m715 m-16

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