Law of Conservation of Energy Homework PE = 20,000 KE = 0 J TE = 20,000 Top PE =15,000 KE = TE =20,000 Point 1 PE = KE =10,000 TE =20,000 Point 2 PE =5,000 KE = TE =20,000 Point 3 PE =0 KE =20,000 TE = Bottom Given an object thrown in the air vertically, indicate the values of KE, PE and TE for the top of the trajectory, Points 1,2, 3 and bottom of the trajectory (during the trip down). NOTE: Points 1, 2, and 3 are evenly spaced distances