Question
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2NH4I(aq)PbI2(s)+2NH4NO3(aq) 1. What volume of a 0.610M NH
Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction
Pb(NO3)2(aq)+2NH4I(aq)PbI2(s)+2NH4NO3(aq)
1. What volume of a 0.610M NH4I solution is required to react with 257 mL of a 0.140 M Pb(NO3)2 solution?
volume:
2. How many moles of PbI2 are formed from this reaction?
moles:
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Fundamentals of Analytical Chemistry
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
9th edition
495558281, 978-0495558286
