Let $[$a$,$b$]$ denote a pair of bytes a and b$.$ The $16-$bit integer corresponding to $[$a$,$b$]$ using big$-$endian conversion is a$\backslash$times $256+$ b; using little$-$endian conversion it is a $+256\backslash$times b$.$

$($a$).$ Find the ones$-$complement sum of $[200,150]$ and $[90,230]$ by using big$-$endian conversion to the respective $16-$bit integers $51,350$ and $23,270.$ Convert back to two bytes, again using big$-$endian conversion, at the end.

$($b$).$ Do the same using little$-$endian conversion, in which case the $16-$bit integers are $38,600$ and $58,970.$