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Let {an} (n>=1)be a sequence for which a(n+1) = (3an+1)/(an+3) for n>=1 (a) Prove that, if a 1 > -1, the sequence {a n }
Let {an} (n>=1)be a sequence for which a(n+1) = (3an+1)/(an+3) for n>=1
(a) Prove that, if a 1 > -1, the sequence {a n } converges.
Hint: consider the cases -1 < an <1, 1
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Graph Colouring And Applications
Authors: Pierre Hansen ,Odile Marcotte
1st Edition
0821819550, 978-0821819555
