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Let f(x) == 4ln(x+6) x+6 +2 Determine the absolute extrema of f on [5, -1]. If multiple such values exist, enter the solutions using
Let f(x) == 4ln(x+6) x+6 +2 Determine the absolute extrema of f on [5, -1]. If multiple such values exist, enter the solutions using a comma-separated list. The absolute minimum of f is and it occurs at x= The absolute maximum of f is and it occurs at x =
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