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Let f(x) be a function with f(1)=2,f(1)=3,f(2)=5,f(2)=1,f(3)=7,f(3)=4,f(4)=1,f(4)=2 Define h(x)=[f(x2)]5 and find h(1) [ 5:41 PM ] For the function f(x)=(x+e3)ln(x+1) What is f(0) ? 1st
- Let f(x) be a function with f(1)=2,f(1)=3,f(2)=5,f(2)=1,f(3)=7,f(3)=4,f(4)=1,f(4)=2 Define h(x)=[f(x2)]5 and find h(1)
- [5:41 PM]For the function f(x)=(x+e3)ln(x+1) What is f(0) ?
1st one use chain rule
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