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Let L be the linear transformation defined by: L Xz X3 Xu (XS) -1 11 1 = -2 2 -3 3 3 3 3

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Let L be the linear transformation defined by: L Xz X3 Xu (XS) -1 11 1 = -2 2 -3 3 3 3 3 -1-1-3 1 I 1 1-2 2 2 1 kernel basS : Image basis: *** MJA X4 X5 ed Find a basis for the kernel of L & a basis for the image (range) of

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To find the kernel and image range of the linear transformation L we need to find the vectors that map to the zero vector and the vectors that are the ... blur-text-image

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