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Let one round of a game of chance have an average score of $8 with a standard deviation of $2. We will play 100 independent

Let one round of a game of chance have an average score of $8 with a standard deviation of $2. We will play 100 independent rounds of this game. Match the quantity with its give-or-take value (standard error). For 100 plays, our total score is likely to be around $800, give or take: For 100 plays, our average score is likely to be around $8, give or take: Our score on any single play is likely to be around $8, give or take: A. $0.02 B. $0.20 C. $2 D. $20 E. $200

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