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Let s(t) = - 24t + 35t - 12t + 7 where s represents the position (displacement), at time t, of an object moving on
Let s(t) = - 24t" + 35t - 12t + 7 where s represents the position (displacement), at time t, of an object moving on a straight line, where t is measured in seconds. Consider such an object over the time interval [0, 9]. Determine the position of the object at t = 0 and t = 9. The object's position at t = 0 is feet The object's position at t = 9 is feet Determine the average rate of change of the object over the time interval [0, 9]. The object's average rate of change over [0, 9] is: ft/sec Determine the instantaneous rate of change (velocity), speed, and acceleration of the object at t = 2. The object's velocity at t = 2 is ft/sec The object's speed at t = 2 is ft/sec The object's acceleration at t = 2 is ft/sec- At what time over 0, 9), if any, did the object change directions? If multiple solutions exist, enter the solutions using a comma-separated list. O The object changed directions at > = O The object did not change directions over [0, 9]
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