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Let us assume algorithm-1 runs in T_(1)(n)=(1)/(2)n^(2) steps, algorithm- 2 takes T_(2)(n)=6nlogn+6n steps for a input of size n. For what values of n (mention
Let us assume algorithm-1 runs in
T_(1)(n)=(1)/(2)n^(2)
steps, algorithm- 2 takes
T_(2)(n)=6nlogn+6n
steps for a input of size n. For what values of
n
(mention the interval) does algorithm-2 performs better than algorithm-1. (10 pt)
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