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Let X 1 , X 2 , ..., X 9 be a sample of Normal random variables with expectation =72 and variance 2 =49. (Namely,

Let X1, X2, ..., X9be a sample of Normal random variables with expectation =72 and variance 2=49. (Namely, standard deviation of =7.) Consider the statistic T = (X-72)/[S/ 9], whereXis the sample average and S2is the sample variance. The probability P(T 2) is best described by:

Select one:

a.0.95

b.0.96

c.0.97

d.0.98

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