Let's find a recurrence relation for The base case is 1 where The recurrence relation is used to relate In to the base case Io. To achieve this we must successively reduce the value of n using integration by parts. Assuming n 1: Io z e- dx = 2 = xe u = xn u' where = In = 6 2e-7 dz. [uv] 1 Souv'dz In v=e=x V = Note the strategic choice of u ensures the power an is reduced. With these choices of u,v we have = 1 = [ 2e- da = w dz So uv' 1 In = [uv] - [ u' vdx uv dx=nIn-1 & P