Let's take the derivative of sinh - (x). Since sinh (sinh - (x)) = differentiating both sides with respect to z leads us to cosh sinh (x) ) d sinh (z) Number Now using the identity cosh (x) - 1 + sinh-(x), we can simplify cosh(sinh -(z)) = 1 + sinh2 (sinh-1(z)) = So dx (sinh ] (z) = Of course, your table of standard integrals will remind you that de - sinh (2) to So the table of integrals can help you remember derivatives, too