lim h0 (2 + h)4 - 16 h We do so by evaluating the function f(h) = (2 + h)4 - 16 for various values of h close to the left side and the right side of h = 0. Intuitively, we do this because then we should be able to h find a value of f(h) as close to the limit as we like if we choose h sufficiently close to 0. Complete the tables for f(h) evaluated at the given values, correct to six decimal places. h f(h) h f(h) 0.5 -0.5 21.875000 0.1 34.481000 -0.1 0.01 32.240801 -0.01 31.760799 0.001 0.0001 -0.001 -0.0001