lim (sin(x+4)-sin(4)) = 04-2 sin(x+4)= sin(2) cos(4)-cos(x) sin(4) sin(z) sin(4) + cos(2) cos(4) b sin(a) sin(4) cos(a) cos(4) sin(z) cos(4) + cos(x) sin(4) So sin(x+4)-sin(4) = sin(z) cos(4)+ sin(4) (cos(z) - 1) sin(z) cos(4) + cos(z) sin(2) sin(x+4)-sin(4) 0 sin(z) cos(4) sin(4)(cos(z) - 1) H + sin(4) sin(4)- 2 2 Part 2 of 5 Part 3 of 5 Part 4 of 5 Part 5 of 5 So sin(x+4)-sia(4) sin(z) cos(4) sin(4) (cos()-1) U lim lim