link : for practice and question 1 -5

https://dcmathpathways.shinyapps.io/LinearRegression/

STAT_6E_Practice Score: 0.67/12 0/5 answered Question 1 Let's put together everything you've learned in this unit about simple linear regression. Our goal in this assignment is to use a cat's body weight to predict how much its heart weighs. When veterinarians prescribe heart medicine for cats, the dose is often based on the size of a cat's heart. As you might imagine, it would be very difficult to weigh a cat's heart in a veterinarian's office, so we want to use a line of best fit that can be used to estimate the cat's heart weight based on its body weight. The dataset' contains the body weight in kilograms (kg) and heart weight in grams (g) for 144 domestic cats. Here are the variables we will use: Sex: Factor with levels "F" and "M" But: Body weight in kg Hwt: Heart weight in g The first 10 observations are displayed in the following table. Sex But Hwt F 2 7 F 2 7.4 F 2 9.5 TI 2.1 7.2 TI 2.1 7.3 TI 2.1 7.6 2.1 8.1 TI 2.1 8.2 2.1 8.3 F 2.1 8.5l' .J. 0.3 lVenables, W. N. & Ripley, B. D. (2002). Modern applied statistics with 5. (4th ed.). Springer. Score on last try: 0.67 of 2 pts. See Details for more. > Next question You can retry this question below Before tting a line of best fit, let's visualize the relationship between the heart and body weight of domestic cats. PartA: What are the explanatory and response variables? Explanatory variable is sex (male or female) and response variable is body weight (in kilograms). O Explanatory variable is sex (male or female) and response variable is heart weight (in grams). 0 Explanatory variable is body weight (in kilograms) and response variable is heart weight (in grams). 0 Explanatory variable is heart weight (in grams) and response variable is body weight (in kilograms). Go to the Linear Regression tool at mpswdcmathpathwaysshinygppsjo/LinearRegression/ __' and plot the data using the following steps: under "Enter Data," select "Enter Own;" name the m (explanatory) and y (response) variables appropriately; copy and paste the data from DCMP STAT 6E Cats __ (make sure the explanatory variable is in the first column and the response variable is in the second column); under "Plot Options," select "Regression Line;" and click \"Submit Data" button. Part B: Use the plot to describe the relationship between body weight and heart weight for cats. Fill in the blanks. There is a strong. V o" , linear relationship between a cat's body weight and its x 0\" heart weight E Calculator Submit Question STAT_6E_Practice Progress saved Score: 0.67/12 0/5 answered . Question 2 Use the tool to calculate a line of best fit to describe the relationship between the two variables. Part A: Write the equation of the line using customized variable names. heart weight = Select an answer |+ Select an answer | x body weight Part B: Interpret the slope of the model. Fill in the blanks. For every Select an answer v| increase in body weight, we predict an average |Select an answer | of Select an answer v | g in the heart weight of cats. Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer | a meaningful interpretation since it |Select an answer | possible for a cat to weigh Select an answer v . Additionally, the intercept is |Select an answer , and it wouldn't make sense for a cat to have a Select an answer | heart weight. Calculator Submit QuestionUse the tool to calculate a line of best fit to describe the relationship between the two variables. Part A: Write the equation of the line using customized variable names. heart weight = > Select an answer Select an answer v | x body weight -0.357 -4.034 Part B: Interpret 1 4.034 . Fill in the blanks. 0.357 For every |Select a body weight, we predict an average |Select an answer v of Select an answer v g in the heart weight of cats. Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer | a meaningful interpretation since it Select an answer v possible for a cat to weigh Select an answer v . Additionally, the intercept is Select an answer , and it wouldn't make sense for a cat to have a Select an answer v | heart weight. Calculator Submit QuestionUse the tool to calculate a line of best fit to describe the relationship between the two variables. Part A: Write the equation of the line using customized variable names. heart weight = Select an answer v + V Select an answer x body weight -0.357 0.357 Part B: Interpret the slope of the model. -4.034 4.034 For every Select an answer v increase in ct an average Select an answer v of Select an answer v | g in the heart weight of cats. Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer | a meaningful interpretation since it Select an answer v| possible for a cat to weigh Select an answer v . Additionally, the intercept is Select an answer , and it wouldn't make sense for a cat to have a Select an answer v | heart weight. CalculatorPart B: Interpret the slope of the model. Fill in the blanks. For everj '/ Select an answer crease in body weight, we predict an average of Select an 0357 kg rt weight of cats. 1 kg Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept a meaningful interpretation since it possible for a cat to weigh . Additionally, the intercept is , and it wouldn't make sense for a cat to have a heart weight. E Calculator Part B: Interpret the slope ofthe model. Fill in the blanks. For every increase in body weight, we predict an averagi v! Select an answer f g in the heart weight 0f cats- decrease increase Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept a meaningful interpretation since it possible for a cat to weigh . Additionally, the intercept is , and it wouldn't make sense for a cat to have a heart weight. E Calculator Part B: Interpret the slope of the model. Fill in the blanks. For every | Select an answer v | increase in body weight, we predict an average Select an answer v of V Select an answer in the heart weight of cats. 0.357 4.034 Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer a meaningful interpretation since it Select an answer v possible for a cat to weigh Select an answer v . Additionally, the intercept is |Select an answer , and it wouldn't make sense for a cat to have a Select an answer v heart weight. CalculatorPart C: Does the intercept have a meaningful interpretation? if so. interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercep v! Select an answer meaningful interpretation since it Select an answer v possible for a cat to weig has Additionally, the intercept is Select an answer v , and it wouldn't make sense does not have eat an answer v heart WEIght. a Calculator Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept a meaningful interpretation since i 'x Select an answer assible for a cat to weigh . Additionally, the intercept is Sela is wouldn't make sense for a cat to have a heart weight. is not Q Calculator Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer v a meaningful interpretation since it possible for a cat to weigl '/ Select an answer Additionally, the intercept is , and it wouldn't make sense 1 0 kg act an answer v heart weight. . 3.357 kg E Calculati 2034 kg Submit Question Part C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer | a meaningful interpretation since it Select an answer v |possible for a cat to weigh Select an answer v . Additionally, the intercept i v Select an answer and it wouldn't make sense for a cat to have a Select an answer v heart weigh positive zero Calculator negative Submit QuestionPart C: Does the intercept have a meaningful interpretation? If so, interpret the intercept. Otherwise, briefly explain why not. Fill in the blanks. The intercept Select an answer v a meaningful interpretation since it Select an answer v possible for a cat to weigh Select an answer v | Additionally the intercept is Select an answer , and it wouldn't make sense for a cat to have : v Select an answer eart weight. negative Calculator 0 kg positive Submit QuestionSTAT_6 E_Practice Score: 0.67/12 0/5 answered 0 Question 3 v Before using the line for prediction, let's see if the model is an appropriate fit for the data and useful for prediction. Make a scatterplot of the residuals versus predicted ("tted") values and a histogram of the residuals. To create the scatterplot and a histogram of the residuals, select the following options in the Fitted Values and Residual Analysis tab. Type of Residuals: 0 Raw Standardized Plot Residuals: Versus Explanatory Variable 0 Versus Fitted Values Select Variable(s} for Hover Info HistogramiBoxplot of Residuals Part A: Based on the scatterplot of the residuals versus predicted, is the line an appropriate fit for the data? 0 No; the points on the plot are not randomly scattered, so the line is not an appropriate t for the data. 0 No; the points on the plot are randomly scattered, so the line is not an appropriate t for the data. 0 Yes; the points on the plot are randomly scattered, so the line is an appropriate fit for the data. 0 Yes; the points on the plot are not randomly scattered, so the line is an appropriate fit for the data. Part B: Calculate R2 and interpret this value. Part B: Calculate R and interpret this value. R2 = % Interpretation (Fill in the blanks): % of thi Select an answer the heart weight of cats can be explained by its Select an answer variation e body weight. decreases increasesPart B: Calculate R and interpret this value. R2 % Interpretation (Fill in the blanks): % of the Select an answer V in the heart weight of cats can be explained by its V Select an answer lationship with the body weight. exponential non-linear linear regression standard error. Briefly describe what this value means in the context of the data.Part C: Calculate the regression standard error. Briefly describe what this value means in the context of the data. Se g Description (Fill in the blanks): grams is the V Select an answer e expect if we use the Select an answer for prediction. increase typical error Hint decreasePart C: Calculate the regression standard error. Briefly describe what this value means in the context of the data. 3.. =l lg Description (Fill in the blanks): l lgrams is the we expect if we use thl '/ Select an answer r prediction. line of best fit model summary Hint residual standard deviation E Calculator STAT_6 E_Pra ctice Score: 0.67/12 0/5 answered 0 Question 4 v Aveterinarian is preparing heart medicine prescriptions for three cats. She wants to use the line to predict their heart weights, which will help her determine the proper doses. For each cat, determine if it's appropriate to use the model to predict that cat's heart weight. If it is appropriate, calculate the predicted value. If it is not appropriate, explain why not. Part A: Buttercup, who weighs 2.2 kg Appropriate? 0 Yes, it is appropriate to use the model since this cat's body weight is within the range of values used to fit the line. 0 No, it is not appropriate to use the model since the cat's body weight is not within the range of values used to t the line. Predicted heart weight: 0 8032 grams 0 Not appropriate to use the model 0 10.35 grams 0 9.127 grams 0 8.518 grams Part B: Freckles, who weighs 6.5 kg Appropriate? O No, it is not appropriate to use the model since the cat's body weight is not within the range of values used to t the line. 0 Yes, it is appropriate to use the model since this cat's body weight is within the range ofvalues used to fit the line. Predicted heart weight: 0 25.435 grams 0 26.127 grams 0 Not appropriate to use the model 0 25.863 grams 0 25.012 grams Part C: Tigger, who weighs 3.8 kg Appropriate? O No, it is not appropriate to use the model since the cat's body weight is not within the range of values used to t the line. 0 Yes, it is appropriate to use the model since this cat's body weight is within the range ofvalues used to fit the line. Predicted heart weight: 0 14.972 grams 0 14.033 grams 0 Not appropriate to use the model 0 15.518 grams 0 13.635 grams STAT_6E_Practice Score: 0.67/12 0/5 answered Question 5 Would you recommend the veterinarian use the predictions from your line as the sole values of heart weight used to determine the dosages of heart medicine prescribed to cats? Explain why or why not using your responses to Questions 3 and 4. Edit Insert Formats BIU X X A wr- V Calculator