link is just to find critical t-value. not needed to solve

Based on the exam scores below for Group 1 and Group 2, test if the average score of Group 1 is greater than that of Group 2 is significantly different statistically. Use the link (click here) for the critical t-value. Select significance level at .05 (meaning 95% confidence level regarding our conclusion.) What is your conclusion from this analysis? NOTE: The null hypothesis: Mean of Group 1 = Mean of Group 2 Alternative hypothesis: Mean of Group 1> Mean of Group 2 The difference of means between the two groups is significant enough. So, accept the null hypothesis. Reject the null hypothesis. Reject both the null and alternative hypotheses. Accept the null hypothesis. Based on the exam scores below for Group 1 and Group 2, test if the average score of Group 1 is greater than that of Group 2 is significantly different statistically. Use the link (click here) for the critical t-value. Select significance level at. 05 (meaning 95% confidence level regarding our conclusion.) What is your conclusion from this analysis? NOTE: The null hypothesis: Mean of Group 1 = Mean of Group 2 Alternative hypothesis: Mean of Group 1> Mean of Group 2 The difference of means between the two groups is significant enough. So, accept the null hypothesis. Reject the null hypothesis. Reject both the null and alternative hypotheses. Accept the null hypothesis