List the possible rational zeros. I! (I) =x4+ 13x2+1t+ 14 If there is more than one answer, separate them with commas. Select "None\" if applicable. The possible national zeros of I! (I): D . List the possible rational zeros. f (x) =4x 4 - 12x - 7x- + 14 If there is more than one answer, separate them with commas. Select "None" if applicable. The possible rational zeros of f (x): O +0 0.O. NoneFind all the zeros. Write the answer in exact form. h(x)=x' -5x-+2x+12 If there is more than one answer, separate them with commas. Select "None" if applicable. +0 The zeros of h (x) : XFind all the zeros. Write the answer in exact form. p (x) =3x +13x -3x- -33x-20 If there is more than one answer, separate them with commas. Select "None" if applicable. The rational zeros of p (x) : XFind all the zeros. Write the answer in exact form. p(x) = x 4 2 - X -90 If there is more than one answer, separate them with commas. Select "None" if applicable. The zeros of p (x) : 0,/0 0.0.... None XA polynomial f (x) and one or more of its zeros are given. f(x) =x*-14x +48x-+70x-265 7 -2i is a zero Part: 0 / 3 Part 1 of 3 (a) Find all the zeros. Write the answer in exact form. 0.O. If there is more than one answer, separate them with a comma. OVE Select "None" if applicable. X The zeros of f (x) :Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of - w / U (multiplicity 2) and W / N (multiplicity 1) and with f (0) = 150. f ( x ) = X 5Write a polynomial f (x) that satisfies the given conditions. Express the polynomial with the lowest possible leading positive integer coefficient. Polynomial of lowest degree with lowest possible integer coefficients, and with zeros 3 -2/ and 0 (multiplicity 3). f ( x) = X 5Espanol Apply Descartes' Rule of Signs. Determine the number of possible positive and negative real zeros for the given function. g (x) =9x +5x -6x -3x +9x-+6x+4 Each part may have more than one possibility. Use commas to separate multiple responses. Part 1 of 2 Number of possible positive real zeros: 0.0.... X 5 Part 2 of 2 Number of possible negative real zeros: 0.O.... X 5Apply Desoartes' Rule of Signs. Determine the number of possible positive and negative real zeros for the given function. 1 .5 l 4 l 1 l = + + HI) 3;: +2.1: 2;: 1' Each part may:r have more than one possibility. Use commas to sepamte multiple responses. Number of possible positive real zeros: D Number of possible negative real zeros: D