Listed in the accompanying table are sample times (seconds) that animated children's movies showed the use of tobacco. The bootstrap method is planned to be used to construct a 90% confidence interval estimate of the population mean u. For this sample data, what is a bootstrap sample? 0, 0, 155, 1, 0, 0, 0, 206, 176, 0, 165, 74, 117, 205, 0 Choose the correct answer below. O A. 15 sample means, each generated by randomly selecting a fixed number of the times in the provided sample with replacement and finding the mean of those times O B. Less than 15 of the times in the provided sample, selected randomly with replacement O C. 15 sample means, each generated by randomly selecting a fixed number of the times in the provided sample without replacement and finding the mean of those times O D. More than 15 of the times in the provided sample, selected randomly with replacement O E. Less than 15 of the times in the provided sample, selected randomly without replacement OF. 15 of the times in the provided sample, selected randomly with replacementListed in the accompanying table are sample times (seconds) that animated children's movies showed the use of tobacco. The bootstrap method is planned to be used to construct a 90% confidence interval estimate of the population mean p. For this sample data, what is a bootstrap sample? 0, 0, 155, 1, 0, 0, 0, 206, 176, 0, 165, 74, 117, 205, 0 Choose the correct answer below. O A. 15 sample means, each generated by randomly selecting a fixed number of the times in the provided sample with replacement and finding the mean of those times O B. Less than 15 of the times in the provided sample, selected randomly with replacement O C. 15 sample means, each generated by randomly selecting a fixed number of the times in the provided sample without replacement and finding the mean of those times O D. More than 15 of the times in the provided sample, selected randomly with replacement O E. Less than 15 of the times in the provided sample, selected randomly without replacement OF. 15 of the times in the provided sample, selected randomly with replacementClaim: Fewer than 12% of homes have only a landline telephone and no wireless phone. Sample data: Asurvey by the National Center for Health Statistics showed that among 15,966 homes 5.83% had landline phones without wireless phones. Complete parts (a) and (b). a. Express the original claim in symbolic form. Let the parameter represent a value with respect to homes that have only a landl'ne telephone and no wireless phone. EB (Type an integer or a decimal. Do not round.) Claim: Fewer than 92% of adults have a cell phone. In a reputable poll of 1103 adults: 85% said that they have a cell phone. Find the value of the test statistic. The value of the test statistic is :|. (Round to two decimal places as needed.) Claim: The standard deviation of pulse rates of adult males is more than 11 bpm. For a random sample of144 adult males, the pulse rates have a standard deviation of 12.3 bpm. Find the value of the test statistic. The value of the test statistic is _ (Round to two decimal places as needed.) The test statistic of z = 2.18 is obtained when testing the claim that p = 0.2. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. This is a test.The test statistic of z = 2.11 is obtained when testing the claim that p .I' 0.265. This is a two-tailed test. Using a 0.05 significance level: complete parts (a) and (b). Click here to view the standard normal distribution table for negative 2 scores. Click here to view the standard normal distribution table for positive 2 scores. a. Find he critical value(s}. Select the correct choice below and fill in the answer box(es) within your choice. [Round 0 two decimal places as needed.) '4." A- "here is one critical value; the critical value is '5." 3- "here are two critical values; the lower critical value is and the upper critical value is Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: Less than 55% of adults would erase all ottheir personal information online if they could. The hypothesis test results in a P-value of 0.3012. a. State a conclusion about the null hypothesis. {Reject He or fail to reject H0.) Choose the correct answer below. if) A. Reject H0 because the P-value is greater than a. if) B. Reject Ho because the P-value is less than or equal to a. {:1 C. Fail to reject H0 because the Pvalue is greater than a. {:3 D. Fail to reject HD because the Pvalue is less than or equal to u. Identify the type I error and the type II error that correspond to the given hypothesis. The percentage of college students who own cars is equal to 35%. Identify the type I error. Choose the correct answer below. {'1 A. Reject the null hypothesis that the percentage of college students who own cars is equal to 35% when that percentage is actually different from 35%. {it B. Fail to reject the null hypothesis that the percentage of college students who own cars is equal to 35% when the percentage is actually equal to 35%. {'1 C. Reject the null hypothesis that the percentage of college students who own cars is equal to 35% when that percentage is actually equal to 35%. {it D. Fail to reject the null hypothesis that the percentage of college students who own cars is equal to 35% when that percentage is actually different from 35%. Use the results from a survey of a simple random sample of 1205 adults. Among the 1205 respondents. 89% rated 17 themselves as above average drivers. We want to test the claim that E of adults rate themselves as above average drivers. Complete parts (a) through (c). a. Identify the actual number of respondents who rated themselves as above average drivers. D (Round to the nearest whole number as needed.)