$($Longer Problem$)$ Later the course, you will be asked to write a

# menu$-$driven command$-$line program. This program will ask the user to

# select a choice from a menu using a number $($e$.$g$.$ Select $1$ through $5,$

# where choice $5$ exits the program$).$ A while loop is the logical structure

# for handling this because you can repeatedly execute all the choices the

# user selects until the user chooses to exit. For example, you could try

#

# numChoices $=5$

# choice $=$ int$($input$($f$"$Enter a choice between $1$ and $\{$numChoices$\}$:$"))$

# while $($choice$<1$ and choice$>$numChoices$)$:

# choice $=$ int$($input$($f$"$Enter a choice between $1$ and $\{$numChoices$\}$:$"))$

#

# The problem is if a person enters a non$-$digit and you try to cast it

# into an int to check if it has an unacceptable value in your while loop,

# you will get a ValueError exception. So how can we build a while loop

# that checks if the user entered an allowed value? One trick is to avoid

# casting the input into an integer at all. We can do this by building a

# list of the string equivalents of the allowed choices and then use the

# while loop to check if that choice is not in that list.

# $*$ Imagine you are told the menu should have numChoices. Build a list

# that contains the string equivalents of $1$ to numChoices. The range

# command $($described in Section $7\mathrm{.}5\mathrm{.}1$ of your textbook$)$ will be useful

# here. Do this before you request a choice.

# $*$ Once you have built your list of acceptable answers, modify the

# requests for a choice from the user to not cast to int and modify your

# while loop to check the user$$s input against the list of acceptable

# choices. Set numChoices $=5,$ so the acceptable values are $1,2,3,4,5$

# and test that you can ask a person for a choice and the code will keep

# asking for an acceptable choice $($using a while loop$)$ until the person

# enters an acceptable choice.