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lw r2,0(r1) label1: beq r2,r0,label2 # not taken once, then taken lw r3,0(r2) beq r3,r0,label1 # taken add r1,r3,r1 label2: sw r1,0(r2) Question: For the
lw r2,0(r1)
label1: beq r2,r0,label2 # not taken once, then taken
lw r3,0(r2)
beq r3,r0,label1 # taken
add r1,r3,r1
label2: sw r1,0(r2)
Question:
For the given code, what is the speedup achieved by moving branch execution into the ID stage? Explain your answer. In your speedup calculation, assume that the additional comparison in the ID stage does not affect clock cycle time..
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