M, a soli Next content resource 5 kg, R=0.133 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.590 kg mass, I.e., J. TOO N. Calculate the angular acceleration of the cylinder. R M Submit Answer Tries 0/20If instead of the force F an actual mass m = 0.590 kg is hung from the string, find the angular acceleration of the cylinder. R M m Submit Answer Tries 0/20 How far does m travel downward between 0.630 s and 0.830 s after the motion begins? Submit Answer Tries 0/20 The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.546 m in a time of 0.550 s. Find Icm of the new cylinder