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M String 1 has a linear massdensity of 23 g/cm and string 2 has a linear mass density of 4] g/cm. They are under tension
M String 1 has a linear massdensity of 23 g/cm and string 2 has a linear mass density of 4\"] g/cm. They are under tension due to a hanging block of mass M : 550g, Calculate the wave speed in each string. (a) v(string1) : 0.484 (b) 11(st'rin92) : I 0.363 lm/s V 2 M M2 The block is now divided into two blocks of masses Mi and M2, as shown in the figure. Find Mi and M2 such that the wave speeds in the two strings are equal. (a) M1: 197.7 9 197.7 (b) M2: 352.3 9
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