M9L3

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Summary In this lesson, we focused on studying the electric field. Atest charge is defined as a positive charge so small that the force it exerts does not significantly alter the distribution of the charges that cause the field being measured. The electric field, E, that exists at a given point is the electrostatic force F experienced by a small test charge g, placed at that point divided by the charge itself. F E= qu The electric field is a vector, and its direction is the same as the direction of the force F on a positive test charge. The Sl unit of electric field is the newton per coulomb, (N/C). The force that a charge g experiences when placed in an electric field E'is F=Eq Since electric field strength is a vector, two or more electric fields would add as vectors do. It is important to state both the magnitude and the direction of the result. The magnitude of the electric field caused by a charge g at a distance r from the charge is E=kL r If g is positive, then E is directed away from q. On the other hand, if g is negative, then E is directed toward g since a negative charge and a positive charge attract each other. In a parallel plate situation, the electric field lines are straight and point away from the positive plate towards the negative plate. Question(s): The physics of electric field between two charges. 1. What is the magnitude and direction of the electric field at a point midway between a -8.0 uC charge and a +6.0 puC charge. The -8.0 uC charge is 4.0 cm to the left of the +6.0 uC charge. 2. If a charge of -2.0 C was placed at the midway point, what force (magnitude and direction) would act on the charge