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main ITV COURSE RE - Definite Integrals Course Packet on properties of the definite integral - Definite Integrals Course Packet on the average value of

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main ITV COURSE RE - Definite Integrals Course Packet on properties of the definite integral - Definite Integrals Course Packet on the average value of a function 16 Suppose f is continuous on [3,16] and f(t) dt = 8. Compute each of the following values 13 12 (a) f (t) dt = 12 ( b ) f ( t ) dt = 16 16 (0) / 6f(t) dt = 16 (d) f (t) + 6 dt = X (e) (f) The average value of f(x) on [3,16] =

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