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Majesty video production inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad length follows a normal distribution

Majesty video production inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad length follows a normal distribution with a popular standard deviation of 2 seconds. Suppose we select a sample of 16 ads produced by Majesty. A. What can we say about the shape of the distribution of the sample mean time? B. What is the standard error of the mean time? ROUND YOUR ANSWER TO 1 DECIMAL PLACE C. What percent of the sample means will be greater than 31.25 seconds? ROUND YOUR Z VALUE AND FINAL ANSWER TO 2 DECIMAL PLACES D. What percent of the sample means will be greater than 28.25 seconds? ROUND YOUR Z VALUE AND FINAL ANSWER TO 2 DECIMAL PLACES E. What percent of the sample means will be greater than 28.5 but less than 31.25 seconds? ROUND YOUR Z VALUE AND FINAL ANSWER TO 2 DECIMAL PLACES F. what is the probability that the sampling error would be less than -1.5 or more than 1.5 ROUND YOUR ANSWER TO 4 DECIMAL PLACES Thanks

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