Make Graph and table and some calcultion

(A)=K(A^nlog(A)=logK+nlog(A1 (3) time requised for 5:5 (3) effect +3 toss on Xacrall? ? {1=KV(C02FA0+akVCA022=kCA0 (A)=K(A^nlog(A)=logK+nlog(A1 CCOD=CBMFfor(CBMFCAMF(1)00=(AMF,(BMF)CAMF The concentration C in the reactor at infinite time is given as: CC+=CAw+CC+=CAw+rforCiwrCBxrA=0.195[1+0.0184(T294)]CAifCA=0 The concentrations A and C at any time within the reaction period are given as: CA=(CAmCAn)[onot]+CAnCC=CC[onot]forCCn Once the concentration values of A are obtained using equation (17), equation (9) is then used to determine (rA) values. Then equation (10) is used to make a plot and obtain the values for the reaction order (n) and specific rate constant (k). Equation (8) can be used to determine the conversion. The specific rate constant can also be determined using: Theoretically, the time required to reach steady state is determined by adding the accumulation term to equation ( 3 ): FA=FA(1XA)+(rA)V+dtd(VCA) For a second order liquid phase reaction, equation (19) can be written as: dtdXA=kCA2(1XA)2VCAFAXA Hence, 21XA1xA2XA21XA+1dXA=0tsdt Where 1=kVCA2FA+2kVCA22=kCA (A)=K(A^nlog(A)=logK+nlog(A1 (3) time requised for 5:5 (3) effect +3 toss on Xacrall? ? {1=KV(C02FA0+akVCA022=kCA0 (A)=K(A^nlog(A)=logK+nlog(A1 CCOD=CBMFfor(CBMFCAMF(1)00=(AMF,(BMF)CAMF The concentration C in the reactor at infinite time is given as: CC+=CAw+CC+=CAw+rforCiwrCBxrA=0.195[1+0.0184(T294)]CAifCA=0 The concentrations A and C at any time within the reaction period are given as: CA=(CAmCAn)[onot]+CAnCC=CC[onot]forCCn Once the concentration values of A are obtained using equation (17), equation (9) is then used to determine (rA) values. Then equation (10) is used to make a plot and obtain the values for the reaction order (n) and specific rate constant (k). Equation (8) can be used to determine the conversion. The specific rate constant can also be determined using: Theoretically, the time required to reach steady state is determined by adding the accumulation term to equation ( 3 ): FA=FA(1XA)+(rA)V+dtd(VCA) For a second order liquid phase reaction, equation (19) can be written as: dtdXA=kCA2(1XA)2VCAFAXA Hence, 21XA1xA2XA21XA+1dXA=0tsdt Where 1=kVCA2FA+2kVCA22=kCA