Many nocturnal animals demonstrate the phenomenon of eyeshine, in which their eyes glow various colors at night when illuminated by a flashlight or the headlights of a car (see the photo). Their eyes react this way because of a thin layer of reflective tissue called the tapetum lucidum that is located directly behind the retina. This tissue reflects the light back through the retina, which increases the available light that can activate photoreceptors, and thus improve the animal's vision in low-light conditions. If we assume the tapetum lucidum acts like a concave spherical mirror with a radius of curvature of 0.750 cm, how far in front of the tapetum lucidum would an image form of an object located 30.0 cm away? Neglect the effects of the other structures of the eye, such as the cornea and lens. Eye Lens Cornea Retina Tapetum lucidum Photo courtesy of David Young In response to a camera flash, the eyes of a cat named Einstein glow orange-red due to the reflection of light from the tapetum lucidum located behind the retina. Number 1.03 Units cmsolution ._ Given object distance from tapeturn lucidum is, u = 30 .0 (m Radius of curvature, R = 0.750 (m Relation between radius of Curvature(R ) and focal length (8 ) is , R = 21 - 7 * = R 2 = ) * = 0.750 = 0.375 cm 2 Thus focal length f = 0.375 (mknow that mission formula is wehere, V is image distance a is object distance fis focal length From Sign Conventions four a concave mission , the focal length ( f) is negative the object distance ( 4) is negative . SO U = - 30.0 (m and f= - 0. 375 (mSubstitute the Known values in ( 1) we get , + (- 30 ) -0. 375 30 0. 375 = 0. 375 30 = - 2. 633 V -2. 633 V - 0. 38 cm ( Where - We Sign means that image is in front of tapeturn lucidum ?) Theforce image is formed at 6.38 cm