Map member into relational schema

a$.$ None of these

b$.$ member $($membid$,$ memb$\_$date, memb$\_$type, address, Expiry$\_$date, name, book$\_$id$)$

c$.$ member $($memb$\_$id$,$ memb$\_$date, memb$\_$type, address, Expiry$\_$date, name$)$

d$.$ member $($memb$\_$id$,$ memb$\_$date, memb$\_$type, address, Expiry$\_$date, name$)$