Mass Load Deflection Area Shear stress Strain Shear modulus Kg 0.1 N m m^2 t (Pa) rads Pa 0.981 0.00002 0.0005376 1824.777 0.0004 4561941.964 0.204 2.001 0.00005 0.0005376 3722.545 0.001 3722544.643 0.305 2.992 0.00008 0.0005376 5565.569 0.0016 3478480.748 0.406 3.983 0.00012 0.0005376 7408.594 0.0024 3086914.063 0.508 4.983 0.00017 0.0005376 9269.866 0.0034 2726431.197 0.61 5.984 0.00024 0.0005376 11131.138 0.0048 2318987.165 Load Deflection N mm 0.981 0.02 0.3 2.00124 0.05 2.99205 0.08 0.25 3.98286 0.12 0.2 4.98348 0.17 5.9841 0.24 0.15 0.1 0.05 Deflection (mm) vs Load (N) 0 0 1 2 3 4 st 5 6 7 Section 3: Use the box below to predict the deflection for a 200N load, with the corresponding shear stress and shear strain. Show all calculations. 20 marks Section 4: Determine an experimental value of the shear modulus of rubber (use the average of the values). Compare this experimental value with the actual value and comment on any discrepancy. 20 marks Section 5: Discuss briefly, using your own words, the relationship between shear stress, shear strain and shear modulus. 15 marks Section 6: The rectangular block of polystyrene is bonded to 2 rigid vertical plates as shown in Figure 1. The inner plate is fixed and the outer plate is subjected to a vertical load, P, of 700 N. 50 mm 50 mm 60 mm Outer Plate Outer Plate Polystyrene Polystyrene 200 mm 200 mm Inner Plate Inner Plate Load, P Figure 1. Determine: The shear stress in the polystyrene block The shear strain in degrees in the block The displacement of the outer plate 20 marks Load, P