Mass m $=0\mathrm{.}1$ kg moves to the right with speed v $=0\mathrm{.}28$ m$/$s and collides with an equal mass initially at rest. $$After this inelastic collision the system retains a fraction $=0\mathrm{.}65$ of its original kinetic energy. $$What is the speed VR $($in m$/$s$)$ of the mass which was originally at rest before the collision?

Hints: All motion is in $1$D$.$Ignore friction between the masses and the horizontal surface. $$You will probably need to use the quadratic formula to solve the resulting equations. $$VR must be greater than VL since the masses can't pass through each other!