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Material properties Some conversions 1W=1J/s1N=1kgm/s21m3=1000L Rod-shaped mechanical parts freshly sprayed with a coating must be cured at an elevated temperature. A cylindrical rod of 30mm
Material properties Some conversions 1W=1J/s1N=1kgm/s21m3=1000L Rod-shaped mechanical parts freshly sprayed with a coating must be cured at an elevated temperature. A cylindrical rod of 30mm diameter and 150mm length is heated in a large furnace having walls at 1000K, while air at 400K is circulating at 3 m/s. The cylinder is in cross flow (see diagram), and its surface is gray with an emissivity of 0.5 . You want to determine if the rod can reach the desired curing temperature in this condition. Find appropriate equation to use in the "given information page". To find appropriate fluid properties also in the "given information page", you may first assume the rod is at 800K. Assumptions: (1) the system is at steady-state; (2) When calculating heat exchange between the rod and the furnace wall through radiation, one can assume that the furnace wall is a large blackbody cavity. Starting from first principles (energy balance), derive the equation to calculate the temperature of the rod(Ts). The equation can only contain one symbol, which is the rod temperature (Ts); all other quantities should be numbers. Simplify the equation as much as possible. Material properties Some conversions 1W=1J/s1N=1kgm/s21m3=1000L Rod-shaped mechanical parts freshly sprayed with a coating must be cured at an elevated temperature. A cylindrical rod of 30mm diameter and 150mm length is heated in a large furnace having walls at 1000K, while air at 400K is circulating at 3 m/s. The cylinder is in cross flow (see diagram), and its surface is gray with an emissivity of 0.5 . You want to determine if the rod can reach the desired curing temperature in this condition. Find appropriate equation to use in the "given information page". To find appropriate fluid properties also in the "given information page", you may first assume the rod is at 800K. Assumptions: (1) the system is at steady-state; (2) When calculating heat exchange between the rod and the furnace wall through radiation, one can assume that the furnace wall is a large blackbody cavity. Starting from first principles (energy balance), derive the equation to calculate the temperature of the rod(Ts). The equation can only contain one symbol, which is the rod temperature (Ts); all other quantities should be numbers. Simplify the equation as much as possible
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