MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 ... Chapter 5: Hypothesis Testing with One Sample Chapter 5: Hy score: 2.Y218 U/ L answered Question 1 You are conducting a study to see if the proportion of voters who prefer the Democratic candidate is significantly smaller than 61% at a level of significance of or = 0.01. According to your sample, 42 out of 80 potential voters prefer the Democratic candidate. a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer v (please enter a decimal) H1: ? v Select an answer (Please enter a decimal) c. The test statistic |? ~ = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer ~ | the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 61% at o = 0.01, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is equal to 61%. The data suggest the population proportion is not significantly smaller than 61% at a = 0.01, so there is not sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 61%. The data suggest the population proportion is significantly smaller than 61% at a = 0.01, so there is sufficient evidence to conclude that the proportion of voters who prefer the Democratic candidate is smaller than 61% h. Interpret the p-value in the context of the study. IMG_20221127_17....jpg - IMG_20221127_17...jpg -IMG_20221127_17...jpg - IMG_20221127_17...jpgTECHNICAL COLLEGE O MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 ... Chapter 5: Hypothesis Testing with One Sam h. Interpret the p-value in the context of the study. O There is a 61% chance of a Type | error. O If the population proportion of voters who prefer the Democratic candidate is 61% and if another 80 voters are surveyed then there would be a 5.95% chance fewer than 53% of the 80 voters surveyed prefer the Democratic candidate. O There is a 5.95% chance that fewer than 61% of all voters prefer the Democratic candidate. O If the sample proportion of voters who prefer the Democratic candidate is 53% and if another 80 voters are surveyed then there would be a 5.95% chance of concluding that fewer than 61% of all voters surveyed prefer the Democratic candidate. i. Interpret the level of significance in the context of the study. There is a 1% chance that the proportion of voters who prefer the Democratic candidate is smaller than 61%. There is a 1% chance that the earth is flat and we never actually sent a man to the moon. O If the population proportion of voters who prefer the Democratic candidate is 61% and if another 80 voters are surveyed then there would be a 1% chance that we would end up falsely concluding that the proportion of voters who prefer the Democratic candidate is smaller than 61% O If the proportion of voters who prefer the Democratic candidate is smaller than 61% and if another 80 voters are surveyed then there would be a 1% chance that we would end up falsely concluding that the proportion of voters who prefer the Democratic candidate is equal to 61%. Hint: Help Helpful Videos: Calculations [+] Setup [+] Interpretations ) [+]MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 5: Hypothesis Testing with One Sample Chapter 5: Hypothesis Tes Chapter 5: Hypothesis Tests for a Single Population Proportion Score: 2.92/8 0/2 answered Question 2 Only 19% of registered voters voted in the last election. Will voter participation increase for the upcoming election? Of the 330 randomly selected registered voters surveyed, 79 of them will vote in the upcoming election. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use |Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer (please enter a decimal) H1: ? Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer | the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly higher than 19% at Q = 0.05, so there is statistically significant evidence to conclude that the the percentage of all registered voters who will vote in the upcoming election will be higher than 19%. The data suggest the population proportion is not significantly higher than 19% at a = 0.05, so there is statistically insignificant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be higher than 1%. The data suggest the population proportion is not significantly higher than 19% at ( = 0.05, so there is statistically significant evidence to conclude that the percentage of registered voters who will vote in the upcoming election will be equal to 19%. Type here to searchMATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 6: The Normal Distribution Chapter 6: Normal Dist Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 1 The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 72 minutes and a standard deviation of 14 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. Find the probability that a randomly selected person at the hot springs stays longer then 70 minutes. c. The park service is considering offering a discount for the 5% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount? minutes. d. Find the Inter Quartile Range (IQR) for time spent at the hot springs. Q1: minutes Q3: minutes IQR: minutes Hint: Helpful videos:MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 6: The Normal Distribution Chapte Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 2 Suppose that the weight of seedless watermelons is normally distributed with mean 6.2 kg. and standard deviation 2 kg. Let X be the weight of a randomly selected seedless watermelon. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. What is the median seedless watermelon weight? kg. c. What is the Z-score for a seedless watermelon weighing 7.4 kg? d. What is the probability that a randomly selected watermelon will weigh more than 5.3 kg? e. What is the probability that a randomly selected seedless watermelon will weigh between 5.4 and 6.1 kg? f. The 85th percentile for the weight of seedless watermelons is kg- Hint : Helpful videos:MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 ... Chapter 6: The Normal Distribution Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 3 Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 256 feet and a standard deviation of 40 feet. Let X be the distance in feet for a fly ball. a. What is the distribution of X? X ~ N( b. Find the probability that a randomly hit fly ball travels less than 273 feet. Round to 4 decimal places. c. Find the 80th percentile for the distribution of distance of fly balls. Round to 2 decimal places. feet Hint: Helpful videos: Find a Probability _ [+] Finding a Value Given a Probability " [+] Hint Submit QuestionMATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 6: The Normal Distribution Ch Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 4 The average student loan debt for college graduates is $25,200. Suppose that that distribution is normal and that the standard deviation is $11,450. Let X = the student loan debt of a randomly selected college graduate. Round all probabilities to 4 decimal places and all dollar answers to the nearest dollar. a. What is the distribution of X? X ~ N( b Find the probability that the college graduate has between $35, 150 and $46,200 in student loan debt. c. The middle 30% of college graduates' loan debt lies between what two numbers? Low: $ High: $ Hint: Helpful videos: . Find a Probability = [+] . Finding a Value Given a Probability ) [+]MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 6: The Normal Distribution Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 5 The mean amount of time it takes a kidney stone to pass is 14 days and the standard deviation is 5 days. Suppose that one individual is randomly chosen. Let X = time to pass the kidney stone. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. Find the probability that a randomly selected person with a kidney stone will take longer than 10 days to pass it. c. Find the minimum number for the upper quarter of the time to pass a kidney stone. days. Hint: Helpful videos: Find a Probability ' [+] Finding a Value Given a Probability [+] Hint Submit QuestionMATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 ... Chapter 6: The Normal Distribution Chapter 6: Normal Distribution Score: 0/6 0/6 answered Question 6 The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2950 and standard deviation 697. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X ~ N( b. Find the probability that the customer consumes less than 2566 calories. c. What proportion of the customers consume over 3062 calories? d. The Piggy award will given out to the 2% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award? calories. (Round to the nearest calorie) Hint: Helpful videos: . Find a Probability ' [+] . Finding a Value Given a Probability