MATHEMATICS

ACTIVITY 1

Directions: Please use long bond paper in answering. Answer directly, A. Solve for the value of one variable by substituting the given value of the other variable to make the equation true. No. Equation x - value y- value I. 2x - 3y = 6 4 2 4x+ y = 12 2 3. 7x + 2y = 2 4 8x - y = 25 5 x+ y = 20 10A Determine the location of the following points. 1 ) A ( - 14, 5) 2.) B ( - 3,-6) 3.) C (0,0) 4.) D (7, 0) 5.) E (0, - 11 ) B. Plot the following set of points. Connect the points and determine the geometric figure formed. You may use graphing paper in plotting if you have graphing paper. If you don't have you may use long bond paper in plotting. 1.) (-3, 1 ), (0, 4), (2, 6), and ( - 4,0) 2.) (0, 5), (-5, 0 ) and ( 5, 0) C. Transform standard form to slope-intercept form and vice versa and give the value of A, B, and C. 1.) 3x + 6y = 5 2.) y = - 3x + 7A. Draw the table on your long bond paper and complete it. Number 1 is done for you. POINT SIGN OF ABSCISSA SIGN OF ORDINATE LOCATION 1.) A (3, 6) OI 2.) B (- 4, 6) 3.) C ( 5, -5) 4.) D( - 7, - 7) 5.) E (4,0) 6. ) F( 0, - 1) 7.) G(0, 7) 8.) H( - 3, - 5) 9.) 1 ( 1, 0) 10.) J ( - 6,9) B. Plot each point on one Cartesian Coordinate System. Then, draw a smooth curve from A to L. Use graphing paper in plotting and attached it on your long bond paper. 1) A (8,3) 2.) B (6, 0) 3.) C(0, - 10) 4.) D (- 6, 0) 5.) E(- 8,3) 6.) F ( - 9,9) 7.) G ( - 6, 10) 8.) H( - 3,8 ) 9.) 1(0,6) 10.) J (3 , 8 ) i1.) K ( 6, 10) 12.) L (9,9) C. Transform from standard form to slope-intercept form and vice versa. 1.) 3x - 2y = - 7 2.) y = - 8x + 4 3.) 4x - 3y = 5