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matlab Cartesian coordinates Following is a table of four points in Cartesian coordinates. Some of the points are constituents of a straight line. (However, there
matlab Cartesian coordinates
Following is a table of four points in Cartesian coordinates. Some of the points are constituents of a straight line. (However, there may be a bit of noise.) 1. 16 25 31 21 17 For each point, construct a (0), p) table where o e {0, 300, 600, 900, 1200, 1500} Choose the maximum set of points that are conceivably constituents of the same straight line. Provide the equation for the line both in polar and in Cartesian coordinates a. b. 2. For the image below, manually (using a calculator), perform the forward transform followed by the inverse transform. THIS PROBLEM IS STILL UNDER CONSTRUCTION Using the image of Lena (provided through the CANVAS site), develop and execute a computer code according to the specifications that follow 3. Multiply each pixel by (-1)he x and y are the pixel coordinates Compute the (forward) Fourier transform Take the complex conjugate of the transform Compute the inverse Fourier transform Multiply each pixel by (-1) Following is a table of four points in Cartesian coordinates. Some of the points are constituents of a straight line. (However, there may be a bit of noise.) 1. 16 25 31 21 17 For each point, construct a (0), p) table where o e {0, 300, 600, 900, 1200, 1500} Choose the maximum set of points that are conceivably constituents of the same straight line. Provide the equation for the line both in polar and in Cartesian coordinates a. b. 2. For the image below, manually (using a calculator), perform the forward transform followed by the inverse transform. THIS PROBLEM IS STILL UNDER CONSTRUCTION Using the image of Lena (provided through the CANVAS site), develop and execute a computer code according to the specifications that follow 3. Multiply each pixel by (-1)he x and y are the pixel coordinates Compute the (forward) Fourier transform Take the complex conjugate of the transform Compute the inverse Fourier transform Multiply each pixel by (-1)
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