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[Maximum mark: 12] B : Consider the differential equation 3: = + 11,, where y = 1 when a: = 0. : (a) Show that

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[Maximum mark: 12] B : Consider the differential equation 3: = + 11,, where y = 1 when a: = 0. : (a) Show that z = ya transforms the differential equation into 3: 3.12 = 1:. E _: (b) By solving this differential equation in z, obtain an expression for y in terms of 1:. WWW

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