May someone please help me explain this to someone who knows ZERO calculus. Please include words

4 ( 6 ) . Test 07 x 1/ 9 x2-4 dx = X N9 - 4 lx * 2 Let X - = t 2 d x = dt + 2 dx = - dt - dx = x N q - 4 - dt * 2 Vq - 4t 2 dt X = t 2 = t -) 2 1 9 14 t At dx 192 - x 2 i ( a ) +( ) = -2 sin t 3 / 2 + c sin 2 t ) +c 3 put the value of t= 2 sin 2 3 X + c - nce dx = - sin 1 2 + c 3 x x 19 x2- 4