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Meghan is interested in finding the area under the curve (between the curve and the x-axis) of f(x) = (1/5)x^5 - 31x^3 - 26x^2 +

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Meghan is interested in finding the area under the curve (between the curve and the x-axis) of f(x) = (1/5)x^5 - 31x^3 - 26x^2 + 1440x, shaded between x = 2 and x = 6. Meghan's teacher gives her a formula for finding an estimate of the area between x = 2 and x = 6 with n rectangles having their TOP LEFT CORNERS touching the curve. In = 193056n - 864n3 - 38080n2 -2048 15n4 Meghan realizes that she can find the actual area under the curve with limn-. (In). The resulting calculation is ... 12870.4 12696.8 12725.6 12950.2

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