MeO2(s)=Me(s)+O2(g) (Me: Metal MeO2 : Metal oxide) Gibbs free energy of the formation of one mole of pure MeO2 (s) from pure Me(s) and pure oxygen gas is given as: GT=268970+3.57TlogT57.21T cal at 1737C. a) Calculate the equilibrium constant for the reaction. b) Calculate the equilibrium partial pressure of oxygen for the reaction. c) Predict the possibility of decomposing a pure MeO2 crucible under vacuum of 2105 mmHg at that temperature. Note: R=1.987cal/ degree.mole 1atm=760mmHg