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Meth Bus (385:02) Exam #2 04/05/23 < Question 4 of 9 > The ANOVA summary table for an experiment with four groups, with six
Meth Bus (385:02) Exam #2 04/05/23 < Question 4 of 9 > The ANOVA summary table for an experiment with four groups, with six values in each group, is shown to the right. Complete parts (a) through (d) below. This test: 29 point(s) possible This question: 4 point(s) possible Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. -C a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all four groups have equal population means. Determine the hypotheses. Choose the correct answer below. OA. Ho H =H == H6 H: * * # H6 OC. Ho H==P4 H # 4 Find the test statistic. FSTAT = (Round to two decimal places as needed.) Determine the critical value. F = (Round to two decimal places as needed.) b. What is your statistical decision? evidence to conclude that there is a difference in the population means of the groups. er-tail critical value from the Studentized range distribution? Ho. There is c. At the 0.05 level of signifi Q = (Round to two decir d. To perform the Tukey-Kra Critical range = (Round to sufficient the critical range? insufficient as needed.) OB. Ho H H4 H: Not all the means are equal. OD. Ho H = = 6 H: Not all the means are equal. Submit test Source Among Degrees of Freedom C-1=3 Sum of Squares SSA 180 Mean Square (Variance) MSA=60 F FSTAT = 2.00 groups Within n-c=20 SSW=600 MSW=30 groups Total n-1=23 SST=780 Meth Bus (385:02) Exam #2 04/05/23 Question 4 of 9 > The ANOVA summary table for an experiment with four groups, with six values in each group, is shown to the right. Complete parts (a) through (d) below. This test: 29 point(s) possible This question: 4 point(s) possible Degrees of Freedom C-1=3 Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. C... a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all four groups have equal population means. Determine the hypotheses. Choose the correct answer below. OA. Ho H = =6 H 6 OC. Ho H = *=P4 H * # H4 Find the test statistic. FSTAT = (Round to two decimal places as needed.) Determine the critical value. F = (Round to two decimal places as needed.) b. What is your statistical decision? Ho. There is evidence to conclude that there is a difference in the population means of the groups. gnificance, what is the upper-tail critical value from the Studentized range distribution? lecimal places as needed.) Do not reject -Kramer procedure, what is the critical range? Reject - nd to three decimal places as needed.) OB. Ho H = = 4 H: Not all the means are equal. OD. Ho H = =6 H: Not all the means are equal. Sum of Mean Source Among Squares Square (Variance) SSA=180 MSA=60 groups Within n-c=20 SSW 600 MSW=30 groups Total n-1=23 SST=780 Submit test F FSTAT 2.00
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