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Methyl ethyl ketone ( MEK ) is an important industrial solvent that can be produced dehydrogenating butan - 2 - ol ( Bu ) over

Methyl ethyl ketone (MEK) is an important industrial solvent that can be produced
dehydrogenating butan-2-ol (Bu) over a zinc oxide catalyst [Ind. Eng. Chem. Res., 27.,
272050(1988)]:
BuMEK+H2
The following data giving the reaction rate for the production of MEK were obtained in
a differential reactor at 490C.
Based on the data in this table, the appropriate speed equation is as follows:
-rA=rB=k1PA(1+k2PA)2
According to the value of >0, the Ergun differential equation should be used as follows
shape:
Sea y=PP0, entonces: dydW=-(1+x)2y
Taking into account the previous information, solve the following:
a) Determine the value of the rate constants, k1 and k2, using the data
experimental (it is suggested to linearize the kinetic equation).
b) Graph PP0 and x as a function of the weight of the catalyst throughout the reactor, using a
incoming molar flow of pure butan-2-ol of 10molmin at a temperature of 490C and a
inlet pressure of 10atm. Consider a Wmax=23 kg taking into account the fall of
pressure and =0.03kg-1. Plot P/P0 and
reactor.
c) Determine the weight of catalyst needed to achieve a 90% conversion.
Remember that
dxdW=-rAFA0
CA=CA0(1-xA1+xA)(PP0)(T0T)
For this isothermal process with pressure drop:
PA=PA0(1-xA1+xA)y
It is suggested to use polymath to solve this problem.
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